The oxidation state of chromium is `[Cr(PPh_(3))_(3)(CO)_(3)]` is

Options

A. `+3`
B. `+8`
C. `0`
D. `+5`

Explanation

To determine the oxidation state of chromium in the complex `[Cr(PPh₃)₃(CO)₃]`, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the overall charge of the complex**:
The complex `[Cr(PPh₃)₃(CO)₃]` is neutral, which means the overall charge is 0.

2. **Assign oxidation states to the ligands**:
- **PPh₃ (Triphenylphosphine)**: This is a neutral ligand, so its oxidation state is 0.
- **CO (Carbon monoxide)**: This is also a neutral ligand, so its oxidation state is 0.

3. **Let the oxidation state of chromium be \( x \)**:
We denote the oxidation state of chromium as \( x \).

4. **Set up the equation for the overall charge**:
The total oxidation states in the complex must sum to the overall charge (which is 0):
\[ x + 3(0) + 3(0) = 0 \]
Here, \( 3(0) \) accounts for the three PPh₃ ligands and \( 3(0) \) accounts for the three CO ligands.

5. **Simplify the equation**:
The equation simplifies to:
\[ x + 0 + 0 = 0 \]
Thus, we have:
\[ x = 0 \]

6. **Conclusion**:
The oxidation state of chromium in the complex `[Cr(PPh₃)₃(CO)₃]` is 0.

### Final Answer:
The oxidation state of chromium in `[Cr(PPh₃)₃(CO)₃]` is 0.