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How many moles of NO2^(ɵ) are oxidised t...

How many moles of `NO_2^(ɵ)` are oxidised to `NO_3^(ɵ)` by 2 " mol of "`MnO_4^(ɵ)` in dilute basic medium?

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To solve the question of how many moles of `NO2^(-)` are oxidized to `NO3^(-)` by 2 moles of `MnO4^(-)` in a dilute basic medium, we can follow these steps: ### Step 1: Understand the Reaction In a dilute basic medium, `MnO4^(-)` is reduced to `MnO2`. The oxidation state of manganese changes from +7 in `MnO4^(-)` to +4 in `MnO2`. ### Step 2: Determine the Change in Oxidation State - For `MnO4^(-)`: The oxidation state of manganese is +7. - For `MnO2`: The oxidation state of manganese is +4. ...
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