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10 " mL of " 2 M HCl and 20 " mL of " 1 ...

10 " mL of " 2 M HCl and 20 " mL of " 1 M `HNO_3` and V volume of `5M H_2SO_4` are mixed together and the solution was made upto 5 L. 10 " mL of " this acid solution exactly neutralises 28.6 " mL of " `Na_2CO_3` solution containing 1 g of `Na_2CO_4.10H_2O` in 100 " mL of " water. Calculate the amount of `SO_4^(2-)` ions in grams present in solution.

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To solve the problem step by step, we will follow these calculations: ### Step 1: Calculate the molecular weight of Na2CO3·10H2O 1. **Molecular weight of Na2CO3·10H2O:** - Sodium (Na): 2 × 23 g/mol = 46 g/mol - Carbon (C): 1 × 12 g/mol = 12 g/mol - Oxygen (O): 3 × 16 g/mol = 48 g/mol ...
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