A sample containing 0.4775 of `(NH_(4))_(2)C_(2)O_(4)` and inert material was dissolved in water and made strongly alkaline with KOH which converted `NH_(4)^(o+)` to `NH_(3)` The liberated `NH_(3)` was distilled of `H_(2)SO_(4)` was back titrated with 11.3 " mL of " 0.1214 M NaOH. Calculate (a) `% of (NH_(4))_(2)C_(2)O_(4)=124.10`

Explanation

To solve the problem, we will follow a systematic approach to calculate the percentage of \((NH_4)_2C_2O_4\) in the sample.

### Step-by-Step Solution:

1. **Identify the Given Data:**
- Mass of the sample = 0.4775 g
- Volume of NaOH used in back titration = 11.3 mL
- Molarity of NaOH = 0.1214 M
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