0.3 g of KI is dissolved in 25 " mL of " water. After adding to this solution double its volume of concentration HCl, a solution of `KIO_(3)` is graduaaly added with stirring. Iodine is liberated as first but redissolved. It is observed that 24.1 " mL of " iodate solution is just sufficient to dissolve the iodine. If the iodate solution contains 0.8 g per 100 mL formulate the reaction that has taken place.

Explanation

To solve the problem step by step, we will analyze the given information, perform calculations, and formulate the chemical reactions involved.

### Step 1: Calculate moles of KI
Given:
- Mass of KI = 0.3 g
- Molar mass of KI = 166 g/mol

**Calculation:**
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