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The volatile chloride of an element has ...

The volatile chloride of an element has a vapour density `approx69`. One gram of the chloride on hydrolysis yields hydrochloric acid and compound free of chlorine. Addition hydrochloric acid and compound free of chlorine. Addition of `AgNO_(3)` to this solution precipitates 3.129 g of AgCl. What may be the atomic weight of the element.?

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To solve the problem step by step, we will follow the given information and apply stoichiometric principles. ### Step 1: Determine the Molecular Weight of the Volatile Chloride The vapor density of the chloride is given as 69. The molecular weight (M) can be calculated using the formula: \[ M = 2 \times \text{Vapor Density} \] Substituting the given vapor density: ...
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CENGAGE CHEMISTRY ENGLISH-STOICHIOMETRY-Ex 3.4 (B)
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  7. A sample containing 0.4775 of (NH(4))(2)C(2)O(4) and inert material wa...

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  8. A 0.5 g sample containing MnO(2) is treated with HCl liberating Cl(2) ...

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  9. 0.3 g of KI is dissolved in 25 " mL of " water. After adding to this s...

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  10. 0.5 g of pure iron wire was dissolved in excess of HCl in absence of a...

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  13. When KIO(3) solution is heated with excess of oxalic acid it is found ...

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  16. Determine the probable formula of an acid salt which is an oxidising a...

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