1.53 g of a compound containing only sulphur, oxygen and chlorine after easy hydrolysis with water yielded acid products which consumed 91 " mL of " `(N)/(2)` sodium hydroxide for complete neutralisation in a parallel experiment, 0.4 g of the compound after hydrolysis with water, was treated with excess of `BaCl_(2)` solution and 0.7 g of `BaSO_(4)` was precipitated. What is the formula of the compound?

Explanation

To determine the formula of the compound containing sulfur, oxygen, and chlorine, we can follow these steps:

### Step 1: Analyze the Hydrolysis Reaction
The compound undergoes hydrolysis, yielding acidic products. This suggests that the compound is likely an acid chloride.

### Step 2: Determine the Amount of NaOH Used
The problem states that 91 mL of \( \frac{N}{2} \) sodium hydroxide (NaOH) was used for complete neutralization. We can calculate the number of equivalents of NaOH used:

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