Water is boiled under a pressure of `1.0 atm`. When an electric current of `0.50A` from a `12V` supply is passed for `300`s through a resistance in thermal contact with it, it is found that `0.789 g` of water is vaporied. Calculate the molar internal enegry and enthalpy chnages at boiling point `(373.15K)`.

Explanation

To solve the problem, we will follow these steps:

### Step 1: Calculate the heat energy supplied (Q)
The heat energy supplied by the electric current can be calculated using the formula:
\[ Q = V \times I \times t \]
Where:
- \( V = 12 \, \text{V} \) (voltage)
- \( I = 0.50 \, \text{A} \) (current)
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