The internal enegry change in the conversion of `1.0 mol` of the calcite form of `CaCO_(3)` to the aragonite from is `+0.2kJ`. Calculate the enthalpy change when the pressure is 1 bar, given that the densities of the solids are `2.71` and `2.93 gcm^(-3)`, respectively.

Explanation

To solve the problem, we need to calculate the enthalpy change (ΔH) for the conversion of 1 mole of calcite (CaCO₃) to aragonite at a pressure of 1 bar, given that the internal energy change (ΔE) is +0.2 kJ. We will also use the densities of the solids to find the change in volume (ΔV).

### Step-by-Step Solution:

1. **Identify Given Data:**
- Internal energy change (ΔE) = +0.2 kJ = +200 J (since 1 kJ = 1000 J)
- Pressure (P) = 1 bar = 1 × 10⁵ Pa (since 1 bar = 10⁵ Pa)
- Density of calcite (ρ₁) = 2.71 g/cm³
...