A system has internal energy equal to `U_(1), 450J` of heat is taken out of it and `600J` of work is done on it. The final energy of the system will be

Options

A. (a) `(U_(1) +150)`
B. (b) `(U +1050)`
C. (c) `(U_(1) - 150)`
D. (d) None of these

Explanation

To find the final internal energy of the system, we can use the first law of thermodynamics, which states:

\[ \Delta U = Q + W \]

Where:
- \( \Delta U \) is the change in internal energy,
- \( Q \) is the heat added to the system (positive if heat is added, negative if heat is removed),
- \( W \) is the work done on the system (positive if work is done on the system, negative if work is done by the system).
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