A lead bullet weighing `18.0g` and travelling at `500 m//s` is embedded in a wooden block of `1.00kg`. If both the nullet and the block were initially at `25.0^(@)C`, what is the final temperature of the block containing bullet? Assume no temperature loss to the surrounding. (Heat capacity of wood `= 0.5 kcal kg^(-1) K^(-1)`, heat capacity of lead `= 0.030 kcal kg^(-1) K^(-1))`

Explanation

To solve the problem, we will follow these steps:

### Step 1: Calculate the Kinetic Energy of the Bullet
The kinetic energy (KE) of the bullet can be calculated using the formula:
\[ KE = \frac{1}{2} mv^2 \]
where:
- \( m \) is the mass of the bullet in kg,
- \( v \) is the velocity of the bullet in m/s.
...