Calculate the standard heat of formation of carbon disulphide `(l)`. Given that the standard heats of combusion of carbon `(s)`, sulphur `(s)` and acrbon disulphide `(l)` are `-390, -290.0`, and `-1100.0kJ mol^(-1)`. Respectively.

Explanation

To calculate the standard heat of formation of carbon disulfide (CS2) in liquid state, we can use the given standard heats of combustion of carbon, sulfur, and carbon disulfide.

### Step-by-Step Solution:

1. **Write the combustion reactions and their enthalpy changes**:
- Combustion of carbon (C):
\[
C(s) + O_2(g) \rightarrow CO_2(g) \quad \Delta H = -390 \text{ kJ/mol}
...