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The temperature of a bomb calorimeter wa...

The temperature of a bomb calorimeter was found to rise by `1.617K` when a current of `3.20A` was passed for `27s` from a `12V` source. Calculate the calorimeter constant.

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Enegry absorbed by the calorimeter
`1 xx t xx V = 3.2 xx 27 xx12 = 1036.8 J`
Calorimeter constant `(ms)` can be calculated as,
`q = ms Deltat`
`1036.8 ms xx 1.617`
`ms = 641.187 kJ`
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