The enthalpy of formation of methane at constant pressure and `300 K` is `-75.83 kJ`. What will be the heat of formation at constant volume? `[R = 8.3 J K^(-1) mol^(-1)]`

Explanation

To find the heat of formation at constant volume (ΔU) from the given enthalpy of formation (ΔH) at constant pressure, we can use the following relationship:

\[ \Delta H = \Delta U + \Delta N_g RT \]

Where:
- ΔH = Enthalpy change at constant pressure
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