Whenever an acid is neutralised by a base, the net reaction is
`H^(o+)(aq)+overset(Theta)OH(aq)rarr H_(2)O(l),DeltaH =- 57.1 kJ`
Calculated the heat evolved for the following experiments?
`0.50 mol` of `HCI` solution is neutralised by `0.50mol` of `NaoH` solution.

Explanation

To solve the problem, we need to calculate the heat evolved when 0.50 moles of HCl are neutralized by 0.50 moles of NaOH. The reaction is given as:

\[ H^+(aq) + OH^-(aq) \rightarrow H_2O(l) \]
with a heat change (\( \Delta H \)) of -57.1 kJ for the neutralization of 1 mole of acid with 1 mole of base.

### Step-by-Step Solution:

1. **Identify the Reaction**:
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