The reaction given below
`BaCl_(2)(s) +2H_(2)O(l) rarr BaCl_(2).2H_(2)O,DeltaH^(Theta) =- x kJ` The value of `DeltaH^(Theta)` represents

Options

A. Enthalpy of hydration
B. Enthalpy of solution
C. Enthalpy of atomization
D. None of the above

Explanation

To solve the question regarding the enthalpy change (ΔH°) for the reaction:

\[ \text{BaCl}_2(s) + 2 \text{H}_2\text{O}(l) \rightarrow \text{BaCl}_2 \cdot 2 \text{H}_2\text{O} \quad \Delta H^\Theta = -x \text{ kJ} \]

we need to analyze what the negative enthalpy change signifies in the context of the reaction.

### Step-by-Step Solution:

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