If the enthalpy of combustion of `C`(graphite) is `-393.3kJ mol^(-1)`, then for producing `39.3kJ` of heat the amount of carbon required is

Options

A. `1.5 mol`
B. `0.5mol`
C. `1.2 g`
D. `12 mg`

Explanation

To solve the problem, we need to determine how much carbon (in grams) is required to produce 39.3 kJ of heat, given that the enthalpy of combustion of carbon (graphite) is -393.3 kJ/mol.

### Step-by-Step Solution:

1. **Understand the Enthalpy of Combustion**:
The enthalpy of combustion of graphite is given as -393.3 kJ/mol. This means that when 1 mole of carbon (12 grams) is burned, it releases 393.3 kJ of energy.

2. **Set Up the Proportion**:
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