The heat of neutralisation of aqueous hydrochloric acid by `NaOH` si `x kcal mol^(-1)of HCI`. Calculate the heat of neutralisation per mol of aqueous acetic acid.

Options

A. `0.5 xkcal`
B. `xkcal`
C. `2x kcal`
D. Cannot be calculated from the given data

Explanation

To calculate the heat of neutralization per mole of aqueous acetic acid (CH₃COOH) when neutralized by NaOH, we can follow these steps:

### Step 1: Understand the neutralization reaction
The neutralization reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH) produces sodium chloride (NaCl) and water (H₂O). The reaction can be represented as:
\[ \text{HCl (aq)} + \text{NaOH (aq)} \rightarrow \text{NaCl (aq)} + \text{H₂O (l)} \]

### Step 2: Identify the heat of neutralization for HCl
The heat of neutralization for this reaction is given as \( x \) kcal/mol of HCl. This value represents the energy change when one mole of HCl is neutralized by NaOH.
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