The 'heat of total cracking' of hydrocarbons `DeltaH_(TC)` is defined as `DeltaH` at `298.15 K` and `101.325 kPa` for the process below
`C_(n)H_(m) +(2n-(m)/(2))H_(2)(g) rarr nCH_(4)(g)`
Given that `DeltaH_(TC)` is `-65.2 kJ` for `C_(2)H_(6)` and `-87.4 kJ` for `C_(3)H_(8)`, calculate `DeltaH` for
`CH_(4)(g) +C_(3)H_(8)(g) rarr 2C_(2)H_(6)(g)`

Explanation

To calculate the enthalpy change (ΔH) for the reaction:

\[ \text{CH}_4(g) + \text{C}_3\text{H}_8(g) \rightarrow 2\text{C}_2\text{H}_6(g) \]

we will use the given heats of total cracking (ΔH_TC) for the hydrocarbons involved in the reaction. The values provided are:

- ΔH_TC for C2H6 = -65.2 kJ
- ΔH_TC for C3H8 = -87.4 kJ
...