The ethalpies for the following reactions at `25^(@)C` are given as:
`(1)/(2)H_(2)(g)+(1)/(2)O_(2)(g) rarr OH (g), DeltaH = 10.06 kcal`
`H_(2)(g)rarr 2H(g),DeltaH = 104.18 kcal`
`O_(2)(g) rarr 2O(g),DeltaH = 118.32 kcal`
Calculate the `O-H` bond enegry in the `OH` group.

Explanation

To calculate the O-H bond energy in the OH group using the provided enthalpy changes for the reactions, we can follow these steps:

### Step 1: Write down the given reactions and their enthalpy changes.
1. \(\frac{1}{2} H_2(g) + \frac{1}{2} O_2(g) \rightarrow OH(g), \Delta H = 10.06 \, \text{kcal}\)
2. \(H_2(g) \rightarrow 2H(g), \Delta H = 104.18 \, \text{kcal}\)
3. \(O_2(g) \rightarrow 2O(g), \Delta H = 118.32 \, \text{kcal}\)

### Step 2: Identify the target reaction.
...