Determine the heat of transformaiton of `C_(("dimamond"))rarrC_(("graphite"))` form the following data:
i. `C_(("diamond"))+O_(2)(g) rarr CO_(2)(g), DeltaH^(Theta) =- 94.5 kcal`
ii. `C_(("graphite")) +O_(2)(g) rarr CO_(2)(g),DeltaH^(Theta) =- 94.0 kcal`

Explanation

To determine the heat of transformation of \( C_{\text{(diamond)}} \) to \( C_{\text{(graphite)}} \), we will use the given thermodynamic data from two reactions. Here’s a step-by-step solution:

### Step 1: Write the given reactions with their enthalpy changes.

1. **For diamond:**
\[ C_{\text{(diamond)}} + O_2(g) \rightarrow CO_2(g), \quad \Delta H^{\Theta} = -94.5 \, \text{kcal} \]
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