Calculate the lattice energy of the reaction
`Li^(o+)(g) +CI^(Theta) (g) rarr LiCI(s)`
from the following data:
`Delta_("sub")H^(Theta)(Li) = 160.67 kJ mol^(-1), (1)/(2)D(CI_(2)) = 122.17 kJ mol^(-1)
IP(Li) = 520.07 kJ mol^(-1),E_(A)(CI) = - 365.26 kJ mol^(-1)` and `Delta_(f)H^(Theta)(LiCI) =- 401.66 kJ mol^(-1)`

Explanation

To calculate the lattice energy of the reaction:

\[ \text{Li}^{(o+)}(g) + \text{Cl}^{\Theta}(g) \rightarrow \text{LiCl}(s) \]

we will use the given thermodynamic data and Hess's law. The lattice energy can be derived from the enthalpy changes associated with the formation of LiCl from its elements in their standard states.

### Step-by-Step Solution:

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