When a mole of crystalline sodium chloride is prepared, `410 kJ` of heat is produced. The heat of sublimation of sodium metal is `180.8kJ`. The heat of dissociation fo chlorine gas into chlorine atoms is `242.7kJ`. The ionization energy of `Na` and electron affinity of `Cl` are `493.kJ` and `-368.2 kJ`, respectively. calculate the lattice enegry of `NaCl`.

Explanation

To calculate the lattice energy of NaCl, we can use Hess's law and the given thermodynamic data. Here are the steps to solve the problem:

### Step 1: Write the overall reaction
The formation of NaCl from its elements can be represented as:
\[ \text{Na (s)} + \frac{1}{2} \text{Cl}_2 (g) \rightarrow \text{NaCl (s)} \]

### Step 2: Identify the enthalpy changes involved
1. **Sublimation of sodium**:
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