i. `H_(2)(g) +CI_(2)(g)rarr 2HCI(g),DeltaH =- x kJ`
ii. `NaCI +H_(2)SO_(4) rarr NaHSO_(4) +HCI, DeltaH =- y kJ`
iii. `2H_(2)O +2CI_(2) rarr 4HCI +O_(2),DeltaH =- z kJ`
From the above equations, the value of `DeltaH` of `HCI` is

Options

A. `-x kJ`
B. `-y kJ`
C. `-z kJ`
D. `(-x)/(2) kJ`

Explanation

To find the value of ΔH for HCl from the given reactions, we will analyze the provided equations step by step.

### Step 1: Analyze the first reaction
The first reaction is:
\[ H_2(g) + Cl_2(g) \rightarrow 2HCl(g), \Delta H = -x \text{ kJ} \]
This indicates that the formation of 2 moles of HCl from 1 mole of H2 and 1 mole of Cl2 releases x kJ of energy.

### Step 2: Calculate ΔH for 1 mole of HCl
...