`N_(2(g))+2O_(2(g)) rarr 2NO_(2) +X kJ`
`2NO_((g))+O_(2(g)) rarr 2NO_(2(g))+Y kJ`
The enthalpy of formation of `NO` is

Options

A. `(2X-2Y)`
B. `X-Y`
C. `1//2(Y-X)`
D. `1//2(X-Y)`

Explanation

To find the enthalpy of formation of NO from the given reactions, we will follow these steps:

### Step 1: Write down the given reactions
1. \( N_2(g) + 2O_2(g) \rightarrow 2NO_2(g) \) with enthalpy change \( \Delta H = X \) kJ.
2. \( 2NO(g) + O_2(g) \rightarrow 2NO_2(g) \) with enthalpy change \( \Delta H = Y \) kJ.

### Step 2: Reverse the second reaction
To find the enthalpy of formation of NO, we need to have NO on the product side. Therefore, we reverse the second reaction:
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