Calculate the resonance energy of toluene (use Kekule structure from the following data
`C_(7)H_(8)(l) +9O_(2)(g) rarr 7CO_(2)(g) +4H_(2)O(l)+ DeltaH, DeltaH^(Theta) =- 3910 kJ mol^(-1)`
`C_(7)H_(8)(l) rarr C_(7)H_(8)(g), DeltaH^(Theta) = 38.1 kJ mol^(-1)`
`Delta_(f)H^(Theta) (water) =- 285.8 kJ mol^(-1)`
`Delta_(f)H^(Theta) [CO_(2)(g)] =- 393.5 kJ mol^(-1)`
Heat of atomisation of `H_(2)(g) = 436.0 kJ mol^(-1)`
Heat of sublimation of `C(g) = 715.0 kJ mol^(-1)`
Bond energies of `C-H, C-C`, and `C=C` are `413.0, 345.6`, and `610.0 kJ mol^(-1)`.

Explanation

To calculate the resonance energy of toluene using the given data, we can follow these steps:

### Step 1: Calculate the Enthalpy of Formation of Liquid Toluene (C₇H₈)
We know from the reaction:
\[ C_7H_8(l) + 9O_2(g) \rightarrow 7CO_2(g) + 4H_2O(l) \]
The enthalpy change (ΔH) for this reaction is given as -3910 kJ/mol.

Using the formula:
...