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The standard heat of formation values of...

The standard heat of formation values of `SF_(6)(g), S(g)`, and `F(g)` are `-1100, 275`, and `80 kJ mol^(-1)`, respectively. Then the average `S-F` bond enegry in `SF_(6)`

A

`310 kJ mol^(-1)`

B

`220 kJ mol^(-1)`

C

`309 kJ mol^(-1)`

D

`280 kJ mol^(-1)`

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To find the average S-F bond energy in SF6, we can use the standard heat of formation values provided for the substances involved in the reaction. Here’s a step-by-step solution: ### Step 1: Write the reaction for the formation of SF6 The formation reaction for SF6 from its elements in their standard states is: \[ S(g) + 6F(g) \rightarrow SF_6(g) \] ### Step 2: Write the expression for the enthalpy change (ΔH) of the reaction The enthalpy change for the formation of SF6 can be expressed using the standard heats of formation: \[ \Delta H = \text{(Heat of formation of SF6)} - \left( \text{(Heat of formation of S)} + 6 \times \text{(Heat of formation of F)} \right) \] ### Step 3: Substitute the values into the equation Using the given values: - Heat of formation of SF6 = -1100 kJ/mol - Heat of formation of S(g) = 275 kJ/mol - Heat of formation of F(g) = 80 kJ/mol Substituting these values into the equation: \[ \Delta H = -1100 - \left( 275 + 6 \times 80 \right) \] ### Step 4: Calculate the total heat of formation for reactants First, calculate \(6 \times 80\): \[ 6 \times 80 = 480 \] Now, add the heat of formation of S: \[ 275 + 480 = 755 \] ### Step 5: Calculate ΔH Now substitute back into the ΔH equation: \[ \Delta H = -1100 - 755 = -1855 \text{ kJ} \] ### Step 6: Relate ΔH to bond energy Since the reaction involves the formation of 6 S-F bonds, we can relate ΔH to the bond energy (X) as follows: \[ \Delta H = 6X \] Thus, \[ -1855 = 6X \] ### Step 7: Solve for X (average bond energy) Now, solve for X: \[ X = \frac{-1855}{6} \approx -309.17 \text{ kJ/mol} \] Since bond energies are typically reported as positive values, we take the absolute value: \[ X \approx 309 \text{ kJ/mol} \] ### Final Answer The average S-F bond energy in SF6 is approximately **309 kJ/mol**. ---

To find the average S-F bond energy in SF6, we can use the standard heat of formation values provided for the substances involved in the reaction. Here’s a step-by-step solution: ### Step 1: Write the reaction for the formation of SF6 The formation reaction for SF6 from its elements in their standard states is: \[ S(g) + 6F(g) \rightarrow SF_6(g) \] ...
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