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Enthalpy of hydrogenation of benzene is ...

Enthalpy of hydrogenation of benzene is `DeltaH_(1)` and for cyclohexene is `DeltaH_(2)`. The resonance energy of benzene is

A

`3DeltaH_(1) - DeltaH_(2)`

B

`3DeltaH_(2)-DeltaH_(1)`

C

`3DeltaH_(1) +DeltaH_(2)`

D

`DeltaH_(1) -3DeltaH_(2)`

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To find the resonance energy of benzene based on the enthalpy of hydrogenation of benzene (ΔH₁) and cyclohexene (ΔH₂), we can follow these steps: ### Step 1: Write the hydrogenation reactions - For benzene (C₆H₆): \[ \text{C}_6\text{H}_6 + 3\text{H}_2 \rightarrow \text{C}_6\text{H}_{12} \quad (\Delta H_1) \] - For cyclohexene (C₆H₈): ...
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Hydrogenation of benzene is done by

Heat of hydrogenation of ethene is x_(1) and that of benzene is x_(2) . Hence resonance energy of benezene is

Heat of hydrogenation of cyclohexene to cyclohexane is -28.6kcal // mole. The observed heat of hydrogenation of benezene to cyclohexane is -49.8 kcal // mole. The resonance energy of benzene is :

Explain resonance in benzene.

Heat of hydrogenation of cyclohexene to cyclohexane is -28.6 kcal/mol.The observed heat of hydrogenation of benzene to cyclohexane is -49.8 kcal/mol. Calculate the resonance energy of benzene in kcal/mole.

What is the resonance energy of Benzene in the same units?

The enthalpy of hydrogenation of cyclohexene is -119.5kJ mol^(-1) . If resonance energy of benzene is -150.4kJ mol^(-1) , its enthalpy of hydrogenation would be :

The enthalpy of hydrogenation of cyclohexene is -119.5kJ mol^(-1) . If resonance energy of benzene is -150.4kJ mol^(-1) , its enthalpy of hydrogenation would be :

The enthalpy of hydrogenation of cyclohexene is -119.5kJ mol^(-1) . If resonance energy of benzene is -150.4kJ mol^(-1) , its enthalpy of hydrogenation would be :

If enthalpy of hydrogenation of cyclohexene is [-x kJ mol^-1] and resonance energy of benzene is [-y kJ mol^-1] then the enthalpy of hydrogenation of benzene will be

CENGAGE CHEMISTRY ENGLISH-THERMODYNAMICS-Archives (Subjective)
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