Heat supplied to a Carnot egine is `453.6 kcal`. How much useful work can be done by the engine that works between `10^(@)C`and `100^(@)C`?

Explanation

To solve the problem of how much useful work can be done by a Carnot engine operating between temperatures of 10°C and 100°C with a heat supply of 453.6 kcal, we can follow these steps:

### Step 1: Convert the heat supplied from kcal to kJ
The heat supplied \( Q \) is given as 453.6 kcal. We need to convert this to kilojoules (kJ) using the conversion factor \( 1 \text{ kcal} = 4.184 \text{ kJ} \).

\[ Q = 453.6 \text{ kcal} \times 4.184 \text{ kJ/kcal} = 1897.86 \text{ kJ} \]
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