`5 mol` of an ideal gas expands reversibly from a volume of `8 dm^(3)` to `80 dm^(3)` at a temperature of `27^(@)C`. Calculate the chngae in entropy.

Options

A. `70.26 J K^(-1)`
B. `80.55 J K^(-1)`
C. `95.73 J K^(-1)`
D. `107.11 J K^(-1)`

Explanation

To calculate the change in entropy (ΔS) for the expansion of an ideal gas, we can use the formula for entropy change during an isothermal process:

\[ \Delta S = nR \ln\left(\frac{V_2}{V_1}\right) \]

Where:
- \( n \) = number of moles of the gas
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