Calculate the change in entropy for the following reaction
`2CO(g) +O_(2)(g) rarr 2CO_(2)(g)`
Given:
`S_(CO)^(Theta)(g)=197.6 J K^(-1)mol^(-1)`
`S_(O_(2))^(Theta)(g)=205.03 J K^(-1)mol^(-1)`
`S_(CO_(2))^(Theta)(g)=213.6 J K^(-1)mol^(-1)`

Explanation

To calculate the change in entropy (ΔS) for the reaction:

\[ 2 \text{CO}(g) + \text{O}_2(g) \rightarrow 2 \text{CO}_2(g) \]

we will use the standard entropy values provided:

- \( S^\Theta_{\text{CO}}(g) = 197.6 \, \text{J K}^{-1} \text{mol}^{-1} \)
- \( S^\Theta_{\text{O}_2}(g) = 205.03 \, \text{J K}^{-1} \text{mol}^{-1} \)
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