Calculate the enthalpy of combustion for the following reaction :
`2HC-= CH +5O_(2) rarr 4CO_(2) +2H_(2)O`
The bond energies of `C-H, C-=C, O=O, C=O`, and `O-H` bonds are `414,812, 494,707`, and `436 kJ mol^(-1)`, respectively.

Explanation

To calculate the enthalpy of combustion for the reaction \( 2HC \equiv CH + 5O_2 \rightarrow 4CO_2 + 2H_2O \), we will use the bond energy values provided. The enthalpy change (\( \Delta H \)) can be calculated using the formula:

\[ \Delta H = \text{(Sum of bond energies of reactants)} - \text{(Sum of bond energies of products)} \]

### Step 1: Identify the bonds in the reactants
The reactants are \( 2HC \equiv CH \) and \( 5O_2 \). We need to identify the bonds present:
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