From `N` atoms of an element A when half the atoms transfer on electron to the another atom `405 kJ m01^(-1)` of energy was found to be consumed. An additional energy of `745 kJ mo1^(-1)` was further required to convert all the `A^(Theta)` ions to `A^(o+)`. Calculate the ionisation energy and the electron affinity of atom A in eV .

Explanation

To solve the problem step by step, we need to find the ionization energy and the electron affinity of atom A in electron volts (eV).

### Step 1: Understand the Processes Involved
When half of the `N` atoms of element A transfer an electron to another atom, energy is consumed. This process involves the electron affinity of atom A. The additional energy required to convert all `A^(-1)` ions to `A^(+1)` ions involves ionization energy.

### Step 2: Set Up the Equations
1. For the first process (half of the atoms transferring an electron):
- Energy consumed = 405 kJ/mol
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