Standard enthalpy of formation of `C_(3)H_(7)NO_(2)(s),CO_(2)(g)` and `H_(2)O(l)` are `133.57,-94.05` and `-68.32kcal mo1^(-1)` respectively
Standard enthalpy combustion of `CH_(4)` at `25^(@)C` is `-212.8 kcal mo1^(-1)` Calculate `DeltaH^(Theta)` for the reaction:
`2CH_(4)+CO_(2)+1//2N_(2)rarrC_(3)H_(7)NO_(2)(s)+1//2H_(2)`
Calculate `DeltaU` for combustion of `C_(3)H_(7)NO_(2)(s)`.

Explanation

To solve the problem, we need to calculate the standard enthalpy change (ΔH°) for the reaction:

\[ 2CH_4 + CO_2 + \frac{1}{2}N_2 \rightarrow C_3H_7NO_2(s) + \frac{1}{2}H_2 \]

and then calculate the change in internal energy (ΔU) for the combustion of \( C_3H_7NO_2(s) \).

### Step 1: Calculate the standard enthalpy of formation for \( CH_4 \)

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