Calculate the standard enegry change for the reaction:
`OF_(2)(g) +H_(2)O(g) rarr O_(2)(g) +2HF(g) at 298K`
The standard enthalpies of formation of `OF_(2)(g), H_(2)O(g)`, and `HF(g)` are `+20, -250`, and `-270 kJ mol^(-1)`, respectively.

Explanation

To calculate the standard energy change for the reaction:

\[ \text{OF}_2(g) + \text{H}_2\text{O}(g) \rightarrow \text{O}_2(g) + 2\text{HF}(g) \]

at 298 K, we will follow these steps:

### Step 1: Calculate the Standard Enthalpy Change (\( \Delta H^\circ \))

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