The dissociation pressure of
`CaCO_(3)(s) overset(Delta) rarr CaO(s) +CO_(2)` gets doubled over a tempertaure range of `60` degree around the mean tempertaure of `837^(@)C`. Calculate the enthalpy of dissociation in kcal `mol^(-1)`.

Explanation

To solve the problem, we need to calculate the enthalpy of dissociation of calcium carbonate (CaCO3) based on the information provided about the dissociation pressure doubling over a temperature range. We will use the van 't Hoff equation, which relates the change in equilibrium constant (or pressure) with temperature to the enthalpy change.

### Step-by-Step Solution:

1. **Identify the Given Information:**
- Mean temperature (T_mean) = 837 °C
- Temperature range = 60 °C (which means T1 and T2 are 30 °C above and below T_mean)
- T1 = 837 + 30 = 867 °C
...