The sublimation energy of a metal is `100kJmol^(-1)` and its Ist and Iind `IEs` are `4.0 eV` and `12.0 eV` respectively. The hydration energy of `X^(o+)` is `-380 kJ mol^(-1)` and `X^(2+)` is `-1280 kJ mol^(-1)`. Comment over the stability of two ions in water.

Explanation

To analyze the stability of the two ions \(X^+\) and \(X^{2+}\) in water, we need to calculate the enthalpy change (\(\Delta H\)) for the dissolution of each ion. This involves considering the sublimation energy, ionization energies, and hydration energies.

### Step 1: Calculate \(\Delta H\) for \(X^+\)

1. **Sublimation Energy**: The energy required to convert \(X\) from solid to gas is given as \(100 \, \text{kJ/mol}\).

\[
\Delta H_1 = 100 \, \text{kJ/mol}
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