Calculate `Deltah` for the eaction
`BaCO_(3)(s)+2HCI(aq) rarr BaCI_(2)(aq)+CO_(2)(g)+H_(2)O(l)`
`Delta_(f)H^(Theta) (BaCO_(3)) =- 290.8 kcal mol^(-1), Delta_(f)H^(Theta) (H^(o+)) =0`
`Delta_(f)H^(Theta) (Ba^(++)) = - 128.67 kcal mol^(-1)`,
`Delta_(f)H^(Theta)(CO_(2)) =- 94.05 kcal mol^(-1)`,
`Delta_(f)H^(Theta) (H_(2)O) =- 68.32 kcal mol^(-1)`

Explanation

To calculate the enthalpy change (ΔH) for the reaction:

\[ \text{BaCO}_3(s) + 2 \text{HCl}(aq) \rightarrow \text{BaCl}_2(aq) + \text{CO}_2(g) + \text{H}_2O(l) \]

we will use the standard enthalpy of formation values provided in the question.

### Step 1: Write the equation for ΔH

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