In certan areas where coal is cheap, artificial gas is produced for household use by the ''water gas'' raction
`C(s) +H_(2)O(g) underset(600^(@)C)rarr H_(2)(g) +CO(g)`
Assuming that coke is `100%` carbon, calculate the maximum heat obtainable at `298K` from the combustion of `1kg` of coke,
GIven: `Delta_(f)H^(Theta), H_(2)O(l) =- 68.32 kcal//mol`
`Delta_(f)H^(Theta),CO_(2) (g) =- 94.05 kcal//mol`
`Delta_(f)H^(Theta),CO(g) =- 26.42 kcal//mol`

Explanation

To solve the problem of calculating the maximum heat obtainable at 298 K from the combustion of 1 kg of coke, we will follow these steps:

### Step 1: Determine the moles of coke
Coke is assumed to be 100% carbon. The molar mass of carbon (C) is approximately 12 g/mol.

To find the number of moles in 1 kg (1000 g) of coke:
\[
\text{Moles of coke} = \frac{\text{mass}}{\text{molar mass}} = \frac{1000 \text{ g}}{12 \text{ g/mol}} \approx 83.33 \text{ mol}
...