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Calculate the heat of formation of anhyd...

Calculate the heat of formation of anhydrous `Al_2Cl_6` from the following data:
(i) `2Al + 6HCl (aq) to Al_2Cl_6 (aq) + 3H_2(g), DeltaH = - 239.76 kcal `
(ii) `Al_2Cl_6 (s) + aq to Al_2Cl_6(aq), DeltaH = - 153.69 kcal `
(iii) `H_2(g) + Cl_2(g) to 2HCl (g) , DeltaH = -44kcal`
(iv) `HCl (g) + aq to HCl (aq), DeltaH = - 17.31 kcal`

A

`2AI(s) +6HCI(aq) rarr AI_(2)CI_(6)(aq) +3H_(2)+1004.2 kJ`

B

`H_(2)(g) +CI_(2)(g) rarr 2HCI(g) +184.1 kJ`

C

`HCI(g) +aq rarr HCI (aq) +73.2 kJ`

D

`AI_(2)CI_(6)(s) +aq rarr AI_(2)CI_(6)(aq) +643.1 kJ`

Text Solution

Verified by Experts

To calculate `DeltaH` of the following reaction:
`2AI(s) +3CI_(2)(g) rarr AI_(2)CI_(6)(s)`
`DeltaH = DeltaH_(1) +3DeltaH_(2) +6DeltaH_(3) - 4DeltaH_(4)`
`=- 1004.2 +3 (-184.1) +6 (-73.2) -(-643.1)`
`=- 1004.2 - 552.3 - 439.2 + 643.1`
`=- 1995.57 +643.1`
`=- 1352.6 kJ mol^(-1)`
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