Enthalpy of neutralisation of acetic acid by `NaOh` is `-50.6 kJ mol^(-1)`. Calculate `DeltaH` for ionisation of `CH_(3)COOH`. Given. The heat of neutralisation of a strong acid with a strong base is `-55.9 kJ mol^(-1)`.

Explanation

To calculate the enthalpy change (ΔH) for the ionization of acetic acid (CH₃COOH), we can use the information provided about the enthalpy of neutralization of acetic acid by NaOH and the enthalpy of neutralization of a strong acid with a strong base.

### Step-by-step Solution:

1. **Identify the Reactions**:
- The ionization of acetic acid can be represented as:
\[
\text{CH}_3\text{COOH} \rightleftharpoons \text{CH}_3\text{COO}^- + \text{H}^+
...