If the enthalpy of combustion of diamond and graphite are `-395.4 kJ mol^(-1)` and `-393.6 kJ mol^(-1)`, what is enthalpy change for the `C("graphite") rarr C("diamond")`?

Explanation

To calculate the enthalpy change for the conversion of graphite to diamond, we can use the enthalpy of combustion values provided for both forms of carbon. Here’s a step-by-step solution:

### Step 1: Write the combustion reactions
1. **Combustion of Diamond (C in diamond form)**:
\[ C_{(diamond)} + O_2 \rightarrow CO_2 \quad \Delta H_1 = -395.4 \, \text{kJ/mol} \]

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