Find the enthalpy of formation of hydrogen flouride on the basis of following data:
Bond energy of `H-H` bond `=434 kJ mol^(-1)`
Bond energy of `F-F` bond `=158 kJ mol^(-1)`
Bond enegry of `H -F` bond `=565 kJ mol^(-1)`

Explanation

To find the enthalpy of formation of hydrogen fluoride (HF) based on the given bond energies, we can follow these steps:

### Step 1: Write the reaction for the formation of hydrogen fluoride
The formation reaction of hydrogen fluoride from its elements in their standard states is:
\[ \frac{1}{2} \text{H}_2(g) + \frac{1}{2} \text{F}_2(g) \rightarrow \text{HF}(g) \]

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