Calculate the enthalpy of formation of water, given that the bond energies of `H-H, O=O` and `O-H` bond are `433 kJ mol^(-1), 492 kJ mol^(-1)`, and `464 kJ mol^(-1)`, respectively.

Explanation

To calculate the enthalpy of formation of water (H₂O), we can use the bond energies of the reactants and products involved in the reaction. The reaction for the formation of water from hydrogen and oxygen can be written as:

\[ \text{H}_2(g) + \frac{1}{2} \text{O}_2(g) \rightarrow \text{H}_2\text{O}(l) \]

### Step 1: Identify the bonds broken and formed
- **Bonds broken**:
...