Calculate the resonance enegry of `NO_(2) ( :O-N=O: )`
The measured enthalpy formation of `NO_(2)(Delta_(f)H^(Theta))` is `34 kJ mol^(-1)`. The bond energies given are:
`N -O rArr 222 kJ mol^(-1)`
`N -= N rArr 946 kJ mol^(-1)`
`O = O rArr 498 kJ mol^(-1)`
`N = O rArr 607 kJ mol^(-1)`

Explanation

To calculate the resonance energy of \( NO_2 \) (nitrogen dioxide), we will follow these steps:

### Step 1: Write the balanced chemical equation for the formation of \( NO_2 \)
The balanced equation for the formation of \( NO_2 \) from its elements is:
\[ \frac{1}{2} N_2 + O_2 \rightarrow NO_2 \]

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