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Calculate the standard free energy chang...

Calculate the standard free energy change for the reaction:
`H_(2)(g) +I_(2)(g) rarr 2HI(g), DeltaH^(Theta) = 51.9 kJ mol^(-1)`
Given: `S^(Theta) (H_(2)) = 130.6 J K^(-1) mol^(-1)`,
`S^(Theta) (I_(2)) = 116.7 J K^(-1) mol^(-1)`
and `S^(Theta) (HI) = 206.8 J K^(-1) mol^(-1)`.

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AI Generated Solution

To calculate the standard free energy change (ΔG) for the reaction: \[ H_2(g) + I_2(g) \rightarrow 2HI(g) \] Given data: - ΔH° = 51.9 kJ/mol - S°(H₂) = 130.6 J/K·mol - S°(I₂) = 116.7 J/K·mol ...
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