Enthalpy of neutralisation of acetic acid by `NaOH` is `-50.6 kJ mol^(-1)`. Calculate `DeltaH` for ionisation of `CH_(3)COOH`. Given. The heat of neutralisation of a strong acid with a strong base is `-55.9 kJ mol^(-1)`.

Explanation

To calculate the enthalpy change (ΔH) for the ionization of acetic acid (CH₃COOH), we will use the given data about the enthalpy of neutralization of acetic acid by sodium hydroxide (NaOH) and the enthalpy of neutralization of a strong acid with a strong base.

### Step-by-Step Solution:

1. **Write the reaction for the neutralization of acetic acid with NaOH**:
\[ \text{CH}_3\text{COOH} + \text{NaOH} \rightarrow \text{CH}_3\text{COONa} + \text{H}_2\text{O} \]
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