`CsOH +HCI rarr CsCI +H_(2)O, DeltaH =- 13.4 kcal mol^(-1)……….(i)`
`CsOH +HF rarr CsF +H_(2)O, DeltaH =- 16.4 kcal mol^(-1) ………(ii)`
Calculate `DeltaH` for the ionisation of `HF` in `H_(2)O`.

Explanation

To calculate the enthalpy change (ΔH) for the ionization of HF in water, we will use the provided reactions and their respective enthalpy changes.

### Step-by-Step Solution:

1. **Identify the Given Reactions**:
- Reaction (i):
\[
\text{CsOH} + \text{HCl} \rightarrow \text{CsCl} + \text{H}_2\text{O}, \quad \Delta H_1 = -13.4 \, \text{kcal/mol}
...