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For the equilibrium LiCl.3NH(3)(s)hArr...

For the equilibrium
`LiCl.3NH_(3)(s)hArrLiCl.NH_(3)(s)+2NH_(3)(g),`
`K_(p)=9atm^(2)` at `37^(@)C.` `A5` litre vesssell contains `0.1` mole of LiCl. `NH_(3)` How many moles iof `NH_(3)` should be added to the flask at this temperature to derive the bckward reaction for completionn ?
`Use: R=0.082atm-L//mol K`

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The correct Answer is:
C

`:' LiCl.3NH_(3)(s) hArr LiCi.NH_(3)(s)+2NH_(3)(g) [K_(p)=9("atm")^(2)]`
`:. LiCl.NH_(3)(s)+2NH_(3)(g) hArr LiCl.3NH_(3)(s) [K_(P_(1))=1/9 ("atm")^(-2)]`
`{:(0.1,(a+0.2),),(,,"Initial moles"),(0,a,0.1),(,,"Final moles at Equilibrium"):}`
`:.` Initial moles of `NH_(3)` should be `(a+0.02)` to bring in completion of reaction.
At equilibrium `K_(P_(1))=1/((P'_(NH_(3)))^(2))` or `1/9=1/((P'_(NH_(3)))^(2))`
`:. P'_(NH_(3))=3 "atm"`
`:' PV=nRT`
`3xx5=nxx0.0821xx313`
`:. n=0.5837 i.e. a=0.5837`
`:.` Initial moles of `NH_(3)=a+0.2=0.5837+0.2`
`=0.7837` moles.
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