The equilibrium constant `K_(c)` for `A(g) hArr B(g)` is `1.1`. Which gas has a molar concentration greater than `1`.

Explanation

To solve the problem, we need to analyze the equilibrium constant \( K_c \) for the reaction \( A(g) \rightleftharpoons B(g) \) given as \( K_c = 1.1 \).

### Step-by-Step Solution:

1. **Write the expression for the equilibrium constant \( K_c \)**:
The equilibrium constant for the reaction can be expressed as:
\[ K_c = \frac{[B]}{[A]} \]
where \([B]\) and \([A]\) are the molar concentrations of gases B and A at equilibrium.

2. **Substituting the given value of \( K_c \)**:
We know that:
\[ K_c = 1.1 \]
Therefore, we can write:
\[ \frac{[B]}{[A]} = 1.1 \]

3. **Rearranging the equation**:
From the equation above, we can express \([B]\) in terms of \([A]\):
\[ [B] = 1.1 \times [A] \]

4. **Analyzing the concentrations**:
Since \( [B] \) is equal to \( 1.1 \times [A] \), this indicates that \([B]\) is greater than \([A]\).

5. **Considering possible values**:
If we consider a scenario where \([A] = 1\):
\[ [B] = 1.1 \times 1 = 1.1 \]
Here, \([B]\) is greater than 1.

Now, if we consider another scenario where \([A] = 1.1\):
\[ [B] = 1.1 \times 1.1 = 1.21 \]
Again, \([B]\) is greater than 1.

6. **Conclusion**:
Since we can find values for both \([A]\) and \([B]\) such that both are greater than 1, we conclude that both gases can have molar concentrations greater than 1.

### Final Answer:
Both gases \( A \) and \( B \) can have molar concentrations greater than 1.